Computer Information Systems

Step 1: Enqueue Operation Answer: O(1) Enqueue operation is O(1) because it involves appending to the end. Explanation: In our Queue implementation, adding (enqueue) an element to the end of the Queue is a constant time operation because it simply involves appending the element to the end of the list. This does not depend on the size of the Queue. Step 2: Dequeue Operation Answer: O(n) Dequeue operation is O(n) because it requires shifting all elements after removing the front element. Explanation: Removing (dequeue) an element from the front of the Queue involves removing the element at index 0, which requires shifting all subsequent elements one position to the left to fill the gap. This shifting operation takes linear time relative to the number of elements in the Queue. Final Answer Yes, the O-notation for the enqueue and dequeue operations will change; the enqueue operation will be O(1) (if adding to the end of the list) and the dequeue operation will be O(n) due to the need to shift all elements after removing the front element. Enqueue Operation: O(1) Dequeue Operation: O(n)

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Computer science

Assume we provided our own implementation for a Queue, but our implementation assumes that the front of the Queue is at index 0.

Briefly (in one sentence) explain if the O-notation for the enqueue and dequeue operations for our implementation will change, and if it does change, state what the O-notation will be for these operations.

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